(3x^2+20x+28)/(x+5)

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Solution for (3x^2+20x+28)/(x+5) equation: 


D( x )

x+5 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

x in (-oo:-5) U (-5:+oo)

(3*x^2+20*x+28)/(x+5) = 0

3*x^2+20*x+28 = 0

3*x^2+20*x+28 = 0

DELTA = 20^2-(3*4*28)

DELTA = 64

DELTA > 0

x = (64^(1/2)-20)/(2*3) or x = (-64^(1/2)-20)/(2*3)

x = -2 or x = -14/3

(x+14/3)*(x+2) = 0

((x+14/3)*(x+2))/(x+5) = 0

( x+14/3 )

x+14/3 = 0 // - 14/3

x = -14/3

( x+2 )

x+2 = 0 // - 2

x = -2

x in { -14/3, -2 }

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